trig question: if sinx+cosx=1 then what does sinx - cosx = ???

Answer 1

If sin(x) + cos(x) = 1 then x = x(n) = π*(4*n-1+(-1)^n) / 4 for n a Natural Number including zero.

For n even, cos(x(n)) is one and sin(x(n)) is zero so
sin(x(n)) - cos(x(n)) = -1.
For n odd, sin(x(n)) is one and cos(x(n)) is zero so
sin(x(n)) - cos(x(n)) = 1.

Then sin(x) - cos(x) = { -1,1}

Answer 2

( sinx / (a million - cosx) ) - ( sinx/ (a million + cosx) ) you prefer a hassle-unfastened denominator to subtract the two fractions: ( (sinx (a million + cosx) ) - (sinx(a million - cosx)) ) / ((a million + cosx) (a million - cosx)) Distribute and simplify: (sinx + sinxcosx - sinx + sinxcosx) / (a million - cos²x) be conscious: a million - cos² x = sin² x (2sinxcosx) / sin²x element out a sinx indoors the numerator sinx(2 cosx) / sin²x Sinx reduces out indoors the numerator: 2(cosx / sinx) be conscious: cosx / sinx = cot x 2cotx

Answer 3

sinx + cosx = √2 sin(x + 45) = 1
sin(x + 45) = 1/√2

sinx - cosx = √2 sin(x - 45)
= √2 sin(x + 45 - 90)
= √2 cos(x + 45)

Since sin(x + 45) = 1/√2
cos(x + 45) = ± √(1 - 1/2)
= ±1/√2

So sinx - cosx = ±1

Answer 4

It's sinx^2+cosx^2 that equals 1. Not sinx + cosx.

To answer your question, sinx - cosx, has no answer, unless x is defined.

Answer 5

sinx+cosx = 1
Square both sides,
1+2sinxcosx = 1
=> 2sinxcosx = 0

(sinx - cosx)^2 = 1 - 2sinxcosx = 1
sinx - cosx = ± 1

Example:
sin90+cos90 = 1, and sin90 - cos90 = 1
sin0 + cos0 = 1, and sin0 - cos0 = -1

Answer 6

Warning!

sin^2x + cos^2x = 1

not sinx + cosx = 1

Answer 7

Draw the graphs of sin x and cos x.

If sin x + cos x = 1 then sin x - cos x = sin (x-90)

I could be wrong, and often am.

Answer 8

sinx + cosx is usually unlike 1.

sin90 + cos90=1

because sin90=1
cos90=0

Then sin90-cos90= 1-0= 1

This solution you also have when x=0, 90,180,270,360........

Answer 9

it's actually sin^2 + cos^2=1

Answer 10

the identy is sin^2x + cos^2x = 1

I dont think there is enought information to solve your equation.