and t is measure in seconds. Find the velocity and acceleration of the object when t=2
could someone please explain this to me..I have no clue how to get the velocity (i got 21mph) and 35 for the acceleration which is wrong. thanks for any help:)
2007-12-10 08:35:30 · 3 answers · asked by maybe71400 1 in Science & Mathematics ➔ Mathematics
Velocity is given by the first derivative of s(t), therefore:
ds/dt = 6t + 2
ds/dt = 6*2 + 2 = 14 m/s when t = 2
Acceleration is the first derivative of velocity, therefore:
a = dv/dt = 6 m/s^2
2007-12-10 08:45:55 · answer #1 · answered by achain 5 · 0⤊ 0⤋
s=21 and velocity should s/t=21/2=11.5 m/sec
acceleration - s/(t*t)= 21/4=5.25 m/secSQ
2007-12-10 16:46:54 · answer #2 · answered by madmath 1 · 0⤊ 0⤋
s `(t) = 6t + 2
v = s `(2) = 14 m/s
s "(t) = 6
a = s "(t) = 6 m² /s
2007-12-10 16:48:18 · answer #3 · answered by Como 7 · 2⤊ 0⤋