Triangle Inequalty
a - b < c
a + b > c
6 - 5 < x
1 < x
So x = 1 * 10^(-n), as long as n is a positive real number greater than 1.
No minimum, but the lowest integer value that x works with is 2.
2007-12-10 07:58:46
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answer #1
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answered by Debt Payer 2
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1
2007-12-10 07:57:44
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answer #2
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answered by Molson 3
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x>1. You can get this as close as you like. The smallest whole number value would be 2, but if you allow fractional values (and a very acute angle), this would be one mark above your measurement tolerance for the two shorter sides combined totalling more than the 6 side.
2007-12-10 07:59:19
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answer #3
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answered by Don E Knows 6
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The answer would be 3.316.
Let x = be the smallest value of the side of the triangle;
Sides of the triangle can be computed using the Pythagorean Theorem which says : a squared plus b squared equals c squared.
Using this formula, x squared + 25 = 36
x squared = 36 - 25
x = square root of 11
x = 3.316
2007-12-10 08:29:19
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answer #4
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answered by Ray 1
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x>1
so the smallest value of x= 1.000......01
depends on where u want to round off
as long as x+5 is more than 6, it will be a triangle
Note: x=1 gives you an overlapping line ..will not form a triangle
2007-12-10 07:58:24
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answer #5
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answered by kamal d 3
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x has to be greater than 1 otherwise 5+x wouldn't be as long as the 6 side to reach it. So, it's just over 1. x>1.
2007-12-10 07:57:33
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answer #6
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answered by krohn211 2
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6-5=1 so x mus t be >1
2007-12-10 07:59:11
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answer #7
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answered by santmann2002 7
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