Given that 4x²-4x=a(x+b)²+c Find for x where a,b and c are constants.?

Question

calculate the value of a,b and c
find the coordinates of the min point A

Answer 1

4x^2 - 4x = 4(x^2 - x) complete the square on the x terms

= 4(x^2 - x + 1/4) - 4((1/4)
= 4(x-1/2)^2 - 1

thus, a = 4, b = -1/2 and c = -1

Minimum point is at (1/2, -1) --the vertex of the parabola

Answer 2

4(x ² - x)
4(x² - x + 1/4 - 1/4)
4(x² - x + 1/4) - 1
4(x - 1/2)² - 1
a = 4
b = - 1/2
c = - 1

Min.point at (1/2 , - 1)

Answer 3

Stop cheatin' and do your homework yourself!