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The forces acting on a sailboat are 390N north and 180N east. If the boat(including crew) has a mass of 270 kg, what are the magnitude and direction of the boat's acceleration?

2007-12-10 06:52:52 · 1 answers · asked by x x italian baby x x 1 in Science & Mathematics Physics

1 answers

Fr=sqrt(F1^2 + F2^2)=
Fr= sqrt((390)^2 + 180^2)=
Fr=430 N
Angle A between forces = arcTan(F2/F1)
A= arcTan(390/180)=65.2 deg
a=Fr/m
a= 1.6 m/s^2

a(north ) = a sin(65.2=1.5 m/s^2
a(east) = a cos(65.2)=0.67 m/s^2

2007-12-10 07:01:29 · answer #1 · answered by Edward 7 · 0 1

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