radius of a sphere is increasing at the constant rate of 3mm/s, how fast is the volume changing when SA=10mm^2

Question

real quick and simple if possible, can't get it set up just right.

Answer 1

V= 4/3*pi*r^3
dV/dt= dV/dr*dr/dt = 4pir^2*3 but 4pir^2 is just the surface of the sphere so
dV/dt = 30 mm^3/s