A 1500-kg car is allowed to coast along a level track at a speed of 8.0 m/s. It collides and couples with a 2000-kg triuck, initially at rest and with brakes released. What is the speed of the two vehicles after they collide?
A) 4.4 m/s
B) 6.0 m/s
C) 4.6 m/s
D) 0.75 m/s
The answer I get is 3.4m/s because since the momentum is conserved the answer should be: (8m/s * 1500kg)/(1500kg+2000kg). Can someone confirm this?
2007-12-10 06:36:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Your answer seems right to me, given:
(m1v1i) + (m2v2i) = (m1+m2)Vf
(1500kg*8m/s) + (2000kg*0m/s) = (1500kg+2000kg)*Vf
Vf = (12000 kg*m/s) / 3500 kg
Vf = 3.43 m/s
Best guess is answer A is a typo.
2007-12-10 06:54:06 · answer #1 · answered by Science 2 · 0⤊ 0⤋
Your answer looks right to me.
2007-12-10 06:55:11 · answer #2 · answered by ZikZak 6 · 0⤊ 0⤋
your solution looks ok to me.
2007-12-10 06:56:11 · answer #3 · answered by Chuck 6 · 0⤊ 0⤋
3.43 m/s is correct.
2007-12-10 06:54:47 · answer #4 · answered by gp4rts 7 · 0⤊ 0⤋