Express: x^2 + 6x + 4 in the form (x+p)^2 + q?

Question

Express x^2 + 6x + 4 in the form (x+p)^2 + q where p and q are constants
Can you all the steps of how to do this
Please

Answer 1

Take your problems and separate it into the desired form...

x^2 + 6x + 4 = (x^2 + 6x) + 4

Now for the (x^2 + 6x) you need to complete the square

(x^2 + 6x) becomes (x^2 + 6x +9) = (x+3)^2

Since you added +9 in the square, you need to subract 9 from the whole equation

x^2 + 6x + 4 = (x^2 + 6x) + 4 = (x^2 + 6x +9) +4 -9

Final Answer: (x+3)^2 -5

Answer 2

once you FOIL it, that's the respond. additionally, in case you do no longer understand a thank you to make the superscript (the ²), to write down out exponents, use the carat, that's the ^ image. it would be written out like: x^2 + 6x + 8 besides, FOIL is a mnemonic that stands for First, Outer, inner, final. Multiply the 1st 2 words. x*x = x^2 Then multiply the x and 2. x*2 = 2x Then multiply the x and four. 4*x = 4x And ultimately, multiply 4 and 2. 4*2 = 8 it would look as though this: x^2 + 2x + 4x + 8. once you upload the 2x and 4x, it is going to become 6x. by potential of ways, in case you prefer to understand a thank you to do the ², carry down the alt button and then style 0178. Then permit pass of the alt button.

Answer 3

x^2 + 6x + 4
Now we complete the square - we add and subtract 9 (half of 6 squared) which we can do because thats the same as adding zero:
(x^2 + 6x + 9) - 9+ 4
= (x+3)^2 -5
As required.

Answer 4

x^2+6x+4
x^2+6x+__ +4 (to get the value for __ we must half the -------------------------------coefficient of x first then square it)
6/2=3, 3^2=9 we must also subtract 9 so that its like adding 0
x^2+6x+9-9+4
(x+3)^2-5