First, get rid of the terms under the division signs by cancelling.
a^2b + 2ab^2/ab - 2ab - b^2/b
becomes
a^2b + 2b - 2ab - b
Collect and evaluate like terms ( +2b - b = +b )
a^2b - 2ab + b
All terms contain b, so divide through by b and put it outside brackets.
b(a^2 - 2a + 1)
factorize the term in brackets
b(a - 1)(a - 1) or b(a - 1)^2
2007-12-10 04:57:42
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answer #1
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answered by Owlwings 7
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= a^2b+2b-2ab-b
=a^2b+b-2ab
=b(a^2+1-2a)
=b (a-1)^2
2007-12-10 12:42:11
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answer #2
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answered by Anonymous
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a^2b + 2ab^2/ab - 2ab - b^2/b
= a^2b +2ab -2ab -b
= a^2b-b = b(a^2-1) = b(a-1)(a+1)
2007-12-10 12:41:37
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answer #3
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answered by ironduke8159 7
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look at the pattern of the star constellations like the greeks
2007-12-10 12:39:06
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answer #4
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answered by brutus 1
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it's related to algebra , i think . but the answer will be strange!
it's some thing that we call it etehad in persian!
2007-12-10 12:48:22
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answer #5
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answered by saeede j 2
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dude i dont know but hey use the math cheatinhahah are **** from someone paparer lol
2007-12-10 12:38:16
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answer #6
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answered by NIce Voice 2
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webmath.com give you the anwsers to your question go try it
2007-12-10 12:38:22
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answer #7
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answered by Anonymous
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sorry guy it's my worst subject
2007-12-10 12:47:03
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answer #8
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answered by Anonymous
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Do you want help, or do you want someone to do it for you?
2007-12-10 12:38:46
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answer #9
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answered by sarah jane 7
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Hell No :P
2007-12-10 12:38:11
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answer #10
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answered by Anonymous
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