2007-12-10 04:05:53 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5 + 7 < 4x
4x > 12
x > 3
2007-12-10 06:08:20 · answer #1 · answered by Como 7 · 5⤊ 0⤋
bill is close:
5 - 4x<-7
-4X<-12
4x>12
x>3
ok the only hard part is the switch in the equality. If you are adding or subtracting from both sides of the inequality, the greater than/less then stays the same. However, when you multiply or divide by a negative nuymber (like we did to the equation with the -4, the operator switches direction)
2007-12-10 04:11:13 · answer #2 · answered by someguy_in_halifax 3 · 1⤊ 1⤋
5 - 4x < -7 (4x and 7 to both sides)
5 + 7 < 4x ( add constants and divide both sides by 4)
12/4 < x (simplify fraction)
3 < x (if you prefer x on the left)
x > 3
You only need to change the inequality if you divide or multiply by a negative number.
2007-12-10 04:08:45 · answer #3 · answered by Brian K² 6 · 0⤊ 0⤋
-4x < -7-5
-4x < -12
x = 3
divide the -12 by -4
2007-12-10 04:10:51 · answer #4 · answered by Noorie 3 · 0⤊ 1⤋
-4x < -12
-x < -3
x < 3
2007-12-10 04:08:47 · answer #5 · answered by Bill W 【ツ】 6 · 0⤊ 1⤋