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your answer choices are
1. x=3 y=1
2. x=-2 y=0
3. lines are parallel
4. lines coincide

please show work

2007-12-10 02:49:38 · 10 answers · asked by Deannapril H 1 in Science & Mathematics Mathematics

10 answers

5y = - x + 8
y = (-1/5)x + 8/3

2x + 10y = - 4
10y = - 2x - 4
y = (-1/5)x - 2/5

Lines are parallel
OPTION 3

2007-12-10 03:06:16 · answer #1 · answered by Como 7 · 3 0

Given x+5y = 8 .......(1)
2x+10y = -4......(2)
multiplying eq 1 by 2 we get..
2x+10y =16 ........(3)
substracting eq 1 and eq 3
2x+10y =16
2x+10y =-4
- - +
---------------------------
0 =20 20/0 =infinite
so the answer choice are 3

2007-12-10 04:11:50 · answer #2 · answered by anwar r 1 · 0 1

x+5y=8
x=8-5y
-2x-10y=4

-2(8-5y)-10y=4
-16 +10y -10y =4
-16=4

Therefore has no solution

3. lines are parallel

2007-12-10 02:53:09 · answer #3 · answered by Murtaza 6 · 0 0

3. (Why?)

x + 5y = 8
-or-
x = 8 - 5y

-2x - 10y = 4
divide by -2
x + 5y = -2

but remember that x = 8 - 5y so replace 'x' with "8 - 5y" and...

8 - 5y + 5y = -2
-or-
8 = -2

This is clearly not true, so the lines do not cross (and must be parallel).

2007-12-10 02:52:11 · answer #4 · answered by Anonymous · 0 0

The lines are parallel because the equations are identical except the intercept. I.e., the second equation can be written as:

x + 5y = -2

So they have the same slope but a different intercept.

2007-12-10 02:55:33 · answer #5 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0 0

2x + 10 y = 16
2x + 10y = -8

the lines are parallel

ans is 3.

2007-12-10 02:52:11 · answer #6 · answered by norman 7 · 0 0

Not doing your homework for you, but I would say that the answer is fish

2007-12-10 02:51:17 · answer #7 · answered by Anonymous · 0 0

1 3+5x1=8
3+5+8 correct
2. -2+0=8 incorrect
--------------------------------------------
-2x3-10x1=4
--6-10=4 incorrect
2. -2x-2-10x0=4
4=4 correct
----------------------------------------------
I can't paint here doe 3 and 4, but it's easy.

2007-12-10 02:56:12 · answer #8 · answered by Novak 3 · 0 0

3 i can't i did it in my head

2007-12-10 02:54:06 · answer #9 · answered by engineer_pockets 2 · 0 0

use a graphing clac -.-

2007-12-10 02:55:24 · answer #10 · answered by Anonymous · 0 0

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