How many g of AgNo3 are required to prepare a 500ml solution whose concentration is 2.00 M?

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2007-12-10 02:20:40 · 2 answers · asked by Becky 1 in Science & Mathematics ➔ Chemistry

the molar mass of AgNO3 is
Ag =108 N=14 O3 =3*16 =48
so AgNO3= 108+14+48=170g
A 500mL=0.5L of 2.0M contains 0.5*2 =1 mole
so you need 170g AgNO3

2007-12-10 02:32:49 · answer #1 · answered by maussy 7 · 0⤊ 0⤋

No. moles AgNO3 = volume(L) x molarity
= 0.50 x 2
= 1.0 mole AgNO3
mass AgNO3= No.moles x molar mass
= 1 x 170
= 170 g AgNO3

2007-12-10 03:17:20 · answer #2 · answered by sami_dodeen 3 · 0⤊ 0⤋