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ok so here is the chemistry problem i have been working on...and cant seem to figure out...any ideas anyone on how to complete and answer this problem??

Calculate the wavelength of a photon emitted from an atom which had an electron leave the third quanta level and return to the second level.

2007-12-10 02:11:16 · 3 answers · asked by Riley 1 in Science & Mathematics Chemistry

3 answers

∆ E =A(1/9 - 1/4)= h c/ L
=2.18x10^-18(-0.138)= hc /L
=- 3 x 10^-19 Jole=( 6.63x10^-34)x3x10^8/L
3X10^-19= 19.89X10^-26/L
L = 19.89X10^-26/3X10^-19
= 6.63X10^-7 m wavelength

2007-12-10 04:07:46 · answer #1 · answered by sami_dodeen 3 · 0 0

You must give the atomic number Z of the atom since the energy depends on Z.
the energy is of the form E= -E0*Z^2/n^2
so energy of the third level E3 =-E0*Z^2/9
so energy of the second level level E2=-E0*Z^2/4

energo of the photon E=E3-E2= E0*Z^2(-1/9+1/4)=5*E0*Z^2/36

the wavelength wavelength =hc/E

wavelength = 5*E0*Z^2/(36*h*c)

2007-12-10 02:42:58 · answer #2 · answered by maussy 7 · 0 0

If 30 mph equals 40 4 ft consistent with 2nd set it up as a fraction so it is going to be 40 4 over 30 then set up yet another fraction yet positioned x on proper and the seventy 5 on the backside then in simple terms xross multiply desire this facilitates in case you go with extra helpjust commet

2016-11-14 07:32:45 · answer #3 · answered by ? 4 · 0 0

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