numbers are x , x+2
x+(x+2)=712
2x=712
x=356
numbers are 356 and 358
Larger no is 358
2007-12-10 02:13:45
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answer #1
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answered by Murtaza 6
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The sum of the two consecutive even intergers is found by saying:
x+(x+2)=714
2x-+2=714
2x=712
x=356
x+2=358
:)
good luck!
2007-12-10 10:19:23
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answer #2
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answered by Rebelchild 2
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Let's rewrite this problem in terms of an equation:
[1] x + y = 714
and we know that the relationship between x and y is
[2] y = x + 2
... therefore we can substitue this fact into the 1st equation:
x + y = 714 -----> x + (x + 2) = 714
2x + 2 = 714
2x = 712
x = 356
now refer back to equation [2] to find y,
y = x + 2 ; y = 356 + 2 = 358
the answer is:
x = 356 , y = 358
2007-12-10 10:14:26
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answer #3
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answered by Razor 2
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Let the integers be x and x+2
Their sum: 2x + 2 = 714
2x = 712
x = 356
The larger integer is 358.
that's it! :)
2007-12-10 10:12:43
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answer #4
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answered by Marley K 7
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2n + (2n + 2) = 714
4n = 712
n = 178
Larger integer is (2 x n) + 2 = 358
2007-12-10 10:39:16
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answer #5
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answered by Como 7
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This is impossible to begin with. No two consecutive numbers can both be even.
2007-12-10 10:44:54
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answer #6
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answered by Anonymous
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hi it's me ! your Mother !
2007-12-10 10:24:28
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answer #7
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answered by ケチャッパー 4
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