Here is the problem illustrated...
http://flickr.com/photos/98443290@N00/2100876010/
2007-12-10 01:57:54 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Stinkypuppy is getting warm
2007-12-10 02:03:16 · update #1
mnost1 is wrong... I said so before he even answered the question
2007-12-10 02:05:06 · update #2
steiner1745 is getting hot, but still he's still wrong
2007-12-10 02:20:25 · update #3
Let's find x. x + x-5 + 3x-10 = 20
5x-15= 20
5x = 35
x = 7.
Updated answer:
Then the other 2 sides of the triangle are 2 and 11.
But 7 + 2 = 9 and 9 < 11, so there is no such triangle.
In any triangle the sum of any two sides must
be greater than the 3rd.
Sorry for my earlier bit of nonsense!
2007-12-10 02:12:56 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
If the perimeter is 5*x-15=20, or 5x=35 and C is x in length, I don't see why C shouldn't be 7 in length.
2007-12-10 10:08:32 · answer #2 · answered by ? 3 · 0⤊ 1⤋
The answer is 7 if the perimeter is 20.
you find this by saying
20=x+x-5+3x-10
20=5x-15
35=5x
7=x
2007-12-10 10:12:05 · answer #3 · answered by Rebelchild 2 · 0⤊ 1⤋
The answer is 7
The perimeter is
(x-5) + (3x-10) + x = 20
5x - 15 = 20
5x = 35
x = 7
2007-12-10 10:04:04 · answer #4 · answered by mnost1 3 · 0⤊ 1⤋
It should be 7, unless it's not really a triangle...
2007-12-10 10:02:25 · answer #5 · answered by Stinkypuppy 3 · 0⤊ 0⤋