Show your solution. This question is a problem solving in Algebra.
2007-12-10 00:54:15 · 11 answers · asked by dario r 1 in Science & Mathematics ➔ Mathematics
From the question above these are the 2 equations:
considering x as the small integer
equation 1: x = y-9
equation 2: x+y = 41
from eq 2: y = 41-x;
so replacing y in eq 1 brings us
x = 41-x-9
2x = 32
x = 16
so smallest integer is 16 and if you are interested in largest integer it's 25
Answer: 16
2007-12-10 01:06:45 · answer #1 · answered by Man D. 2 · 0⤊ 0⤋
x=y-9
x+y=41
(y-9)+y=41
2y=41+9
2y=50
y=25
x=16
2007-12-10 00:59:07 · answer #2 · answered by Mike1942f 7 · 0⤊ 0⤋
since it is 9 less than
then 9-x + x =41
x+x=41+9
2x=50
x=25
2007-12-10 01:13:38 · answer #3 · answered by lp342 4 · 0⤊ 1⤋
16
2007-12-10 01:03:06 · answer #4 · answered by Levi 4 · 0⤊ 1⤋
Let the numbers be x & y
==> x - y = 9..................(1)
x+ y = 41.................(2)
solving as simultaneous equations,
2x = 50
==> x = 25
y = 41 - 25
y = 16
==> the smaller integer is 16
2007-12-10 01:15:16 · answer #5 · answered by Joel K 2 · 0⤊ 0⤋
Let The Numbers be X,Y... X be the largest int. and Y be the smallest Int.
Acc to your Prob..
X+Y = 41
Y = X -9
So 2X -9 = 41 --------- OK
2X = 50
X = 25
using the X value 25+ Y = 41
Then Y =16
So the Smallest Integer is 16.....
2007-12-10 01:15:59 · answer #6 · answered by Harry 2 · 0⤊ 1⤋
It is 16.
41-9=32
32/2=16
Check answer:
16+9=25
25+16=41
2007-12-10 00:57:47 · answer #7 · answered by Anonymous · 0⤊ 0⤋
x=y-9
x+y=41
add the equations
2x+y = y +32
so x=16, y=25
2007-12-10 00:57:48 · answer #8 · answered by tsr21 6 · 0⤊ 0⤋
a+b=41
a-b=9
a=25
b=16
25=16=41
25-16=9
2007-12-10 01:25:40 · answer #9 · answered by homer 3 · 0⤊ 1⤋
oh u a 5th grade??
2007-12-10 01:01:34 · answer #10 · answered by detroitmafia 3 · 0⤊ 0⤋