trig question?

Question

change -sqrt3 + i in trigonometric form and find

1. (-sqrt3 + i)^5, answer in rectangular form such as a+bi

2. (-sqrt3 + i)^1/3, wrtite all answers seperately in trigonometric form using degree angles?

please help with this problem I dont understand how to do them and need step by step instruction thanks
20 hours ago - 3 days left to answer.

Answer 1

- √3 + i
= 2 [ - √3/2 + (1/2) i ]
= 2 [ cos(5π/6) + i sin(5π/6) ]

1.
(-sqrt3 + i)^5
= 2^5 * [ cos(5π/6) + i sin(5π/6) ]^5
= 32 [ cos(25π/6) + i sin(25π/6) ]
= 32 [ cos (π/6) + i sin (π/6) ]
= 32 ( √3/2 + (1/2) i )
= 16√3 + 16i

2.
(-sqrt3 + i)^1/3
= 2^(1/3) * [ cos(5π/6) + i sin(5π/6) ]^(1/3)
= 2^(1/3) * [ cos(5π/18) + i sin(5π/18) ]
= (1.2599) * (0.6428 + i 0.7660 )
= 0.81 + i (0.965)

Angles are in radians. To convert in degrees, replace π by 180°