and also can you tell me how you did it?
2007-12-09 23:58:30 · 12 answers · asked by Dillon 1 in Science & Mathematics ➔ Mathematics
76% X = 25000
X = 25000/.76 = 32895 (rounded)
2007-12-10 00:01:47 · answer #1 · answered by fcas80 7 · 2⤊ 2⤋
T = total of 9th graders
.76 T = 25000
T = 25000/.76
2007-12-10 08:10:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Have you got your figures right? Do you mean that 76% graduated and 25000 DIDN'T?
If 76% did and 25000 did that means that 76% is equal to 25000 and that cannot be divided evenly. The answer to that is 328.94736 and that can't be. If 76% graduated and 25000 didn't then 25000 is equal to 24% and that is not right either.
2007-12-10 08:09:01 · answer #3 · answered by leximp 2 · 0⤊ 0⤋
76% = 25,000
25,000/76 = 328.94736842105263157894736842105
which is 1%
x 100 = 32894.736842105263157894736842105
which is 100%
So 32,895.
Note to Marcus Paul answer above:
You ate 75% of your pizza, which was 3 slices. How many slices in all?
It is obvious the answer is 4.
Going on MP's logic, the answer would be 3.75. Which we all know is wrong.
2007-12-10 08:02:38 · answer #4 · answered by Anonymous · 2⤊ 0⤋
let total no of students = x
76% = 25000
24% = ?
= 25000/76 * 24
= 7894.7
Total = 25000 + 7894.7
2007-12-10 08:05:46 · answer #5 · answered by Raga 3 · 0⤊ 0⤋
When trying to establish a number without knowing the gross number (total sum) as in this question, you would multiply the net number against the percentage, and this will provide the answer you seek.
25,000 * .76 = 32,894.73 total students.
Hope this helps!
2007-12-10 08:59:46 · answer #6 · answered by Levi 4 · 0⤊ 0⤋
25000/.76=
32894.7
2007-12-10 08:03:00 · answer #7 · answered by jlrieff 3 · 2⤊ 0⤋
It should be 76% 25000
= 19000
2007-12-10 08:05:38 · answer #8 · answered by Tubby 5 · 0⤊ 4⤋
If 27% of kids do their own homework, and there are 54,000 of them, how many get Yahoo Answers to do it for them instead?
2007-12-10 08:04:03 · answer #9 · answered by candolim_imp 2 · 1⤊ 0⤋
lol
25000x(100/76)
2007-12-10 08:01:50 · answer #10 · answered by Marcus Paul 3 · 1⤊ 4⤋