Math help pleaseeeeeeeeee-WOrd problem?

Question

1)Ann walks 5km in 1 hour,and betty walks 4km in 1 hour.If they start walking toward each other fom a distrance of 36km,How many hours willl it take for them to meet?
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2)Denny walks 60 m in 1 minute,and john travels 210 m in 1 minute by bike.
if denny has already walked 1800 m,how many minutes will it tkae for john to catch up with denny by bike assuming denny continues to walk?

Please show in steps.....

Answer 1

1. The closing velocity will be 5+4 = 9 km/hr. This will cover 36 km in 36/9 = 4 hours.
2. The closing velocity here will be the difference in speed, i.e. 210-60 = 150 m/min. The time required for closure will be 1800/150 = 12 minutes.

Answer 2

1) In 1 hour, Ann would cover 5 km and Betty 4, so in total, the distance between them is getting smaller by 5+4 every hour, that's 9/hr. For them to meet, the whole distance needs to be covered, so you divide 36km by 9km and you get 4 hours.
5km/hr+4km/hr= 9km/hr
36km/(9km/hr)=4 hrs

2)Every minute, John travels the distance Denny travels PLUS 210-60 = 150 m more. So how long will it take this extra 150m per minute to help him make up for the 1800 m he lost? 1800m/(150m/minutes) = 16minutes


I also don't recommend letting Yahoo answers do your math homework for you. It's a kind of cheating and will only come back to bite you later on when you realize you don't know arithmetic as well as you should.

Answer 3

1. time = 36/(5 + 4) hours = 4 hours

2. time J takes = 1800/(210 -- 60) minutes = 12 minutes

Answer 4

for question 2
let denny = y1
let john = y2

Therefore y1 = 60x + 1800
y2 = 210x

the point of intersection equals the time to catch up

therefore let y1 = y2
60x + 1800 = 210x
we can divide each side by 30
now => 2x + 60 = 7x
deduct 2x from each side
=> 60 = 5x
x = 12 minutes

Answer 5

I think I'm too slow for number 2. But here is the answer to number 1:

Ann walks 4 hours, which is equal to 20km for her. In this same amount of time (4 hours) Betty walks 16km. 20km + 16km = 36km. Therefore, starting at a distance of 36km apart they would have to walk for 4 hours to meet each other.

Answer 6

(1) Ann walks at 5 km per hour and Betty at 4 km per hour. Their combined rate is 9 km per hour.

rate * time = distance so time = distance / rate

36 km / (9 kilometers / hour ) = 4 hours


(2)

x_Dennis = 1800m + 60m ( t )
x_John = 210 m ( t )

Set them equal and solve for time

1800 + 60 t = 210 t
1800 = 150 t
12 = t

They will meet in twelve minutes.

Answer 7

1) divide the distance, 36Km, by the speed at which they are appoaching each other:

36 / (5 + 4) = 36 / 9 = 4 hr

2) The distances they have gone will be equal.

Denny's distance: 60t + 1800
John's distance: 210t

210t = 60t + 1800
150t = 1800
t = 12 minutes

Answer 8

ann -> @ 5km/h
betty <- @ 4hm/h

every hour they get 9km closer
36/9 = 4 hours

210 - 60 = 150m closer every minute
1800m distance at the beginning
1800 / 150 = 12 minutes

Answer 9

If some thing is 40% smaller, you in basic terms subtract 40%. So 40% of 40 energy is sixteen: you try this with the help of multiplying 40 with the help of 0.4. the respond could be 40 - sixteen = 24 A shorter way could only be to multiply with the help of 40 with the help of 0.6, because of the fact is a million-0.4.

Answer 10

they walk together of 9km/hr
therefore it takes them 4 hours to walk 36km
the answer is 4 hours

every min john will catch up 150m
in order to catch up 1800m
it takes him 12 min to catch up(1800/150)