How do you simplify this? What method do you have to use? (6y^2+4y-3) + (3y^2+2)?

Answer 1

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(6y^2+4y-3)+(3y^2+2)
=6y^2+4y-3+3y^2+2
=6y^2+3y^2+4y-3+2
=9y^2+4y-1

Answer 2

Jen, the "solution" here is to recognize that adding the two terms can be done by adding the parts inside the parentheses.

that means that 6y^2 +4y -3 added to 3y^2 +2 is the same with or without the parentheses!

so, which parts can be combined arithmetically? hint: -3 and +2 are constants, not variables, so that should be an easy one: -3+2 =2-3 = -1.

no biggie, eh? what's left? the +4y is unique, and there are no other terms to match it, so the answer will include one term of simply +4y.

what's left now? 6y^2 [and without a - sign, it's a +6y^2...] and 3y^2... 3y^2 plus 6y^2 = (3+6)y^2 = 9y^2.

collecting all of the like term, the sum is = (9y^2+4y-1)

the method is to first, recognize that the sum of the two is the sum of the parts, then look for similar [matching] variables in each one and add them accordingly.

for practice, what's (6y^2+4y-3) MINUS (3y^2+2)?

Answer 3

Clear the parentheses.
Combine like terms by adding coefficients.
Combine the constants.

(6y^2+4y-3) + (3y^2+2) = 9 y^2+4 y-1

Answer 4

add the 6y^2 with the 3y^2 , leave the 4y, and add the -3 with +2.

Final answer should be: 9y^2+4y-1

Answer 5

Hi,
What you do is just open the brackets:
6y^2+4y-3+3y^2+2=9y^2+4y-1 This is an answer.
All the best,
Mika

Answer 6

Add "things" that are the same:-
(6y² + 3y²) + (4y) + (2 - 3)
9y² + 4y - 1

Answer 7

9y^2+4y-1

Answer 8

This is simple. Just simplify using algebra and it will become a polynomial. It will be

9y^2+4y-1

Plug it into quadratic formula and you get two zeros.

4 + or - 2sqrt(13) all divided by 9