Is it because the vector created by the 2 bromines cancel the vector of the 2 lone pairs? If so, how can this be? Isn't the vector created by the lone pairs 'stronger' than the vector created by the 2 bromines?
2007-12-09 16:01:56 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
SBr2 is not non polar. It has two bonded electron pairs and to non bonded electron pairs. It is an Sp3 molecule, there is noway for it to be non polar. It is analogous to water. Haveing two bonded pairs and two non bonded pairs. No one here is gonna argue that water is non-polar
2007-12-09 16:51:27 · answer #1 · answered by hipster342000 3 · 1⤊ 1⤋
Is Sbr2 Polar
2016-11-09 23:13:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
At first, I assumed that it was polar because of the Lewis Structure. But when my textbook told me I was wrong, I figured out the problem. The bond between S and Br is a non-polar bond (i.e. because of the electronegativity difference); and once the bond(s) in between the molecule is non polar, then the whole molecule MUST be non polar.
2015-04-24 11:50:48 · answer #3 · answered by Nifemi 1 · 0⤊ 0⤋
No, because they are opposite each other in the molecule, so they cancel each other out. This is also true for the electron vectors. That is why the molecule is non-polar.
Also, the Br's will always be on opposite sides of the molecule (At least theoretically) because that is it's most stable form.
2007-12-09 16:07:07 · answer #4 · answered by CBing 1 · 1⤊ 2⤋
SBr2 is polar. If you look at the three dimensional structure it is not symmetrical. When a structure is symmetrical it is nonpolar.
2014-10-29 13:55:46 · answer #5 · answered by ? 1 · 2⤊ 1⤋
Depends, my son, on the actual orbitals involved.
2007-12-09 16:06:52 · answer #6 · answered by cattbarf 7 · 0⤊ 2⤋
nonpolar
2016-10-08 02:51:57 · answer #7 · answered by Er Manish 1 · 1⤊ 0⤋