2007-12-09 14:19:11 · 5 answers · asked by malorie e 1 in Science & Mathematics ➔ Mathematics
f(x) = (x+3)/sqrt(x+11)
The domain is (-11,inf) because -11 would make the denominator equal to zero, and anything less than that would make the answer imaginary.
f(3) = (3+3)/sqrt(3+11) = 3sqrt(14)/7 =~ 1.6
2007-12-09 14:23:46 · answer #1 · answered by someone2841 3 · 0⤊ 0⤋
Since you have sqrt x+11 and you can't do the sqrt of a negative, and it's on the bottom of a fraction so it can't be zero, x must be > -11. That's the domain. And then plug in 3 for x getting
(3+3) on top and sqrt 11+3 on bottom so 6/â14
2007-12-09 22:23:44 · answer #2 · answered by hayharbr 7 · 1⤊ 0⤋
The domain is all real numbers (the graph will eventually pass over all values of the x axis). f(3) is the same thing as plugging in a 3 for x (3+3 / [root] 3+11). This simplifies to 6/(square root)14.
2007-12-09 22:23:38 · answer #3 · answered by That Gay Guy for Da Ben Dan 5 · 0⤊ 0⤋
12
2007-12-09 22:21:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
eleventeen
2007-12-09 22:26:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋