2007-12-09 14:16:51 · 7 answers · asked by ````andui```` 1 in Science & Mathematics ➔ Mathematics
3(4x+3)(x-1)
2007-12-09 14:25:14 · answer #1 · answered by Harris 6 · 3⤊ 0⤋
12x^2-3x-9 = 3(4x^2-x-3)
= 3(4x+3)(x-1)
2007-12-09 22:31:26 · answer #2 · answered by Matthew T 2 · 0⤊ 0⤋
3(4x^2 - x - 3)
3((4x -3)(x+1)
factors of x are 4x-3 = 0 => 3/4
x+1 =0 => x = -1
2007-12-09 22:22:51 · answer #3 · answered by bindiya 2 · 0⤊ 0⤋
12x^2-3x-9 = 0
3(4x^2-x-3) = 0
(4x^2-x-3) = 0
4x^2-4x+3x-3 = 0
4x(x-1) + 3(x-1) = 0
(4x+ 3) (x-1) = 0
(4x+ 3) = 0
or
(x-1) = 0
x = -3/4 or x=1
2007-12-09 22:27:09 · answer #4 · answered by Shrikant R 2 · 0⤊ 0⤋
3(4x+3) (x-1)
2007-12-09 22:21:29 · answer #5 · answered by MALATHI VEDAGIRI 2 · 0⤊ 0⤋
3(4x^2 - x - 3) = 3(4x+3)(x-1)
2007-12-09 22:20:34 · answer #6 · answered by Anonymous · 0⤊ 1⤋
3(4x^2-x-3)
3(4x+3)(x-1)
2007-12-09 22:44:45 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋