A student of ECSU going on thanksgiving holiday drove a distance of 100 km due north from EC downtown for 50 mins, he stopped at a gas station to buy gas and use the bathroom for 10 mins, he then turned east and traveled a distance of 50 km for 20 mins. He stopped and visited a high school friend for 20 mins. Then he continued his journey by traveling south, another 50 km for 20 mins. And then turned west and traveled 50 km for 15 mins before getting home.
(a) What is the average speed for the entire journey is m/s?
*Could you please show how you got it?
(b) What is the magnitude of the average velocity in m/s?
*Please show work.
(c)In what direction is the average velocity?
2007-12-09 12:47:09 · 1 answers · asked by Rasheena E 1 in Science & Mathematics ➔ Physics
100 km/hr north in 50 min
at rest for 10 min
50 km East in 20 mins
at rest for 20 min
50 km South in 20 min
50 km west in 15 min
a) average speed is distance divided by time
total distance is
250 km
time is 50+10+20+20+20+15
50+10+20+20+20+15
135 min
in m/s
250000*60/135
111111 m/s
b) velocity has direction
Let's look North and South first
The displacement North South is 50 km North
50000*60/135
vy=22222 m/s North
Now East Est
The displacement East West is zero
vx=0
so the magnitude of the average velocity is
22222 m/s
and the direction is North.
j
2007-12-10 04:17:07 · answer #1 · answered by odu83 7 · 0⤊ 0⤋