Did i answers this physics problem correctly?

Question

I was asked to find the experimental weight of a meterstick on a support with a mass on one side.

heres what i did:
Torque left= Torque right
(Fw)(Pivot Point- Center of Gravity)=(Weight of Mass)(Location of mass-Pivot point)

(Fw)(.65-.499)=(2.1152322)(.732-.65)
.151Fw=.300056792
Fw=1.987131073 N

The actual weight is 1.28184 N. So the percent error is like 55% which is way to high. As long as i did the problem right my teacher might understand. Please help me!!

Answer 1

Can't check your numbers, but:

1. Did you calculate the center of gravity of the stick at the half way point between the support and the end?

2. Did you calculate the mass of each portion of the meter stick using its length?

3. Was the mass a point mass or distributed over a length? Either way, did you have its C.G. in the right place?

Torque left = torque right is the right place to begin, and
torque = mass (force) x distance is the right way to continue

but you still have to get the masses and distances right.

Answer 2

How approximately getting a bite of graph paper, draw a huge 'go' on it, good to backside and left-to-good, intersecting interior the middle of the paper. provide each and every graph-sq. a cost of one hundred. North is on the nicely suited South is on the backside. West is on the left and East is on the nicely suited use '-' for down/descents and '+' for up/ascents From there, that is basically an arithmetic situation: including, subtracting, etc. good success.