need some help?

0 ⤊

The base of an isosceles triangle is 8 in. less than the length of the equal sides. If the perimeter of the triangle is 28 in., find the length of each of the sides.

2007-12-09 10:21:22 · 2 answers · asked by m&m 1 in Education & Reference ➔ Homework Help

2 answers

28 = (a-8) + a + a
28 = a - 8 + a + a
28 + 8 = a + a + a
36 = 3a
36/3 = a
12 = a

Therefore the sides are both 12inches and the base is (12-8) 4inches long.

2007-12-09 10:36:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋

OK. Let x = length of 2 equal sides.
Perimeter = x+x+ x-8 = 28
3x-8 = 28
3x = 28+8
3x = 36.
x = 36/3 = 12.

So the 2 equal sides are each 12"
The base is 12"- 8" = 4"

Hope this helps.

2007-12-09 18:37:36 · answer #2 · answered by SKCave 7 · 0⤊ 0⤋