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Solev over the field of complex numbers.?

[1/(x-1)]+[1/(x+1)]
all over
[2/(x-1)]-[1/(x+1)]
equal to 1

2007-12-09 09:20:25 · 1 answers · asked by Olivia 2 in Science & Mathematics ➔ Mathematics

1 answers

= 2x/(2x+2-x+1)= 2x/(x+3)=1 so 2x=x+3 and x=3
(No complex numbers involved)

2007-12-09 09:27:35 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

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