basically, Barb pulled the plug in her bathtub and it started to drain. the amt of water in the bathtub as it drains is rep. by the equation L= -5t^2-8t+120, where L rep. the number of liters of water in the bathtub and "t" rep. the amt of time in min, since the plug was pulled.
1.How many liters of water were in the bathtub when barb pulled the plug?
2. To the nearest tenth of a min., the amt of tieme it takes for all the water in the bathtub to drain.
I used Axis of symmetry(-b/2a)
any more tips of formulas plz help
Thanks in Advance,
~*God-Bless*~
2007-12-09 08:33:03 · 1 answers · asked by modelgyal91 2 in Education & Reference ➔ Homework Help
For the first part set "t" = to zero (before you start draining) and solve the equation; L = 120 liters.
For the second part, set the equation = to zero (no water left) and solve for "t"
-5t^2 -8t + 120 = 0
you should be able to do it now.
2007-12-09 08:47:05 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋