Pure oxygen gas was first prepared by heating mercuric oxide, HgO:
what volume (in liters) of oxygen at STP is released by heating 10.57 g of HgO?
2 HgO(s) --> 2 Hg(l) + O2(g)
2007-12-09 08:02:29 · 3 answers · asked by Mike R 2 in Science & Mathematics ➔ Chemistry
Dear Mike,
Back in the day, we had to answer our own questions on our final exams to get credit.
If we didn't know the answer, we didn't get the points.
Just sayin'
: )
2007-12-09 08:10:40 · answer #1 · answered by ceviche queen 4 · 0⤊ 0⤋
Atomic weights: Hg=200.6 O=16 HgO=216.6
10.57gHgO x 1molHgO/216.6gHgO x 1molO2/2molHgO x 22.4LO2/1molO2 = 0.546 L O2
2007-12-09 16:07:59 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
10.57g HgO x 1moleHgO/216.58g
= .04880 mole HgO
1 mole O2/ 2 mole HgO x .04880 mole HgO
=.0244mole O2 x 22.4 liters/1mole
=.05465 liters
2007-12-09 16:21:32 · answer #3 · answered by ? 5 · 0⤊ 0⤋