help with math!?

0 ⤊

2ln(3x-4)=7
please help me with this and explain it step by step if you don't mind.

2007-12-09 07:18:12 · 3 answers · asked by ashtreylil 3 in Science & Mathematics ➔ Mathematics

3 answers

2ln(3x-4)=7
ln(3x-4) = 7/2 = 3.5
e^ln(3x-4) = e^3.5
3x-4 = e^3.5
3x = 4 + e^3.5
x = (4+e^3.5)/3

2007-12-09 07:28:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋

2ln(3x-4)=7
ln(3x - 4) = 7/2 (divide by 2)
3x - 4 = e^(7/2) (Take e^ on both sides since e^ln(x) = x we have that line)
3x = e^(7/2) + 4
x = (e^(7/2) + 4)/3 by isolating as required.

2007-12-09 15:21:23 · answer #2 · answered by highschoolmathpreparation 3 · 0⤊ 0⤋

2ln(3x-4)=7
ln(3x-4) = 7/2 = 3.5
e^ln(3x-4) = e^3.5
3x-4 = e^3.5
3x = 4 + e^3.5
x = (4+e^3.5)/3

2007-12-09 15:24:41 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋