which element or ion is the best oxidizing agent.?

Question

Use the standard reduction potentials below to determine which element or ion is the best oxidizing agent.

Br2(λ) + 2 e- → 2 Br-(aq) E° = +1.08 V
Hg2+(aq) + e- → Hg(λ) E° = +0.86 V
Ni2+(aq) + 2 e- → Ni(s) E° = -0.25 V

a.Br-
b.Ni2+
c.Ni
d.Hg2+
e.Br2

Answer 1

e.Br2

Answer 2

Best Oxidizing Agent

Answer 3

the oxidizing agent is reduced, the oxidized species is the reducing agent to be oxidized, Cu and Zn need to lose electrons and the ions, Mg2+, Zn2+ and Pb2+ need to gain the electrons. if they gain electrons, they were reduced AND oxidizing agents. 1. Zn2+ + Cu, for Cu to be oxidized, Cu2+ would be formed changing the color of the solution to blue and Zn would ppt out as a solid metal, since no rxn occurred, Cu(s) is stronger oxidizer than Zn2+ but this isnt' saying much. the fact that no rxn occurred tells me that neither metal was oxidized or reduced. so, neither one is an oxidizing agent. 2. see #1 3. Pb2+ + Zn resulted in Zn2+ and Pb(s) formation, Pb2+ is the stronger oxidizing agent in this equation since Zn became Zn2+ by losing 2 electrons. Pb precipitated out as a metal and Zn2+ went into solution. overall, according to only these results, Pb2+ is the stronger oxidizing agent of the 3 reactions

Answer 4

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RE:
which element or ion is the best oxidizing agent.?
Use the standard reduction potentials below to determine which element or ion is the best oxidizing agent.

Br2(λ) + 2 e- → 2 Br-(aq) E° = +1.08 V
Hg2+(aq) + e- → Hg(λ) E° = +0.86 V
Ni2+(aq) + 2 e- → Ni(s) E° = -0.25 V

a.Br-
b.Ni2+
c.Ni
d.Hg2+
e.Br2

Answer 5

the Answer is E, because the more positive the potential the greater the electron pulling power. the oxidizing agent is the one that is reduced, which means it gains electrons, therefore it will pull electrons to itself.