-3x + 4y = 29
3x - 2y = -17
---------------------
2y = 12
y = 6
-3x+ 4(6) = 29
-3x + 24 = 29
-3x = 5
x = -5/3
If there was supposed to be a + sign where the first set of equal signs is then this way
-3x + 4y = 29
3x + 2y = -17
-------------------
6y = 12
y = 2
-3x + 4(2) = 29
-3x + 8 = 29
-3x = 21
x = -7
I'm thinking it is the second way that I worked it. Hope this helps
2007-12-09 06:58:29
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answer #1
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answered by Ms. Exxclusive 5
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If there is no typing error:
-3X + 4Y = 29 Add both equations
3X - 2Y =-17
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2Y = 12 Divide by 2 both sides of equation
Y = 6
Substitute 6 for Y
3X - 12 = -17: 3X = -5: X= -5/3 = -1+2/3
I believe that there is a "typo" in this question
2007-12-09 15:13:45
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answer #2
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answered by gzlakewood@sbcglobal.net 4
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The equations don't work. I think you meant to write
3x+ 2y= -17 for equation 2?
rearrange eqn.1: 4y= 29+3x
therefore 2y= 14.5 +1.5x
sub in eqn. 2: 3x+ (14.5+ 1.5x)= -17
4.5x = -31.5
divide by 4.5: x= -7
sub into eqn. 1: -3(-7) +4y=29
21+4y+29
4y= 8
y= 2
2007-12-09 15:07:26
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answer #3
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answered by Just me 5
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you add the equations together since by doing so the x terms will eliminate themselves
-3x + 4y = 29
3x + 2y = -17
__________
0 + 6y = 12
solve for y, divide by 6
y = 2
Now put 2 back into original equation (either one) for y and solve for x
-3x + 4(2) = 29
-3x + 8 = 29
-3x = 21
x = -7
answer(-7, 2)
2007-12-09 14:58:34
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answer #4
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answered by Linda K 5
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assuming you mean
-3x + 4y = 29
3x + 2y = -17
you add those to eliminate the x varaible
6y = 12, y = 2
plug 2 into one of them to find x
3x + 2(2) = -17
3x = -21
x = -7
2007-12-09 14:59:10
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answer #5
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answered by Blueberry Man 5
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-3x+4y=29
3x+2y=-17
Just add the two equations, getting:
6y = 12
y = 2
Then 3x +2(2) = -17
3x = -21
x = -7
2007-12-09 14:58:50
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answer #6
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answered by ironduke8159 7
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first solve for one of the variables in either of the equation.
substitute it in the other equation (the one which is still in terms of 2 vars) ..
you will get the answer for the 1 variable you solved for .. plug it into any of the other equations you hvae .. and solve for the 2nd unknown var.
there solved using elimination
2007-12-09 14:57:01
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answer #7
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answered by sudhi_kandi 3
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Is there a typo?
2007-12-09 14:57:26
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answer #8
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answered by Vince H 3
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