Physics HW Help?

Question

2.89*10^3 kg takes a circular turn with a radius of 29.6m. Acc. of gravity is 9.81 m/s^2. Flat road, static friction is .74. What is the speed the car can go without skidding? Help please

Answer 1

The force required to move in the circular path is

m v² / r

This is provided by the friction force

μ m g

So set the two forces equal:

m v² / r = μ m g

and solve for the maximum velocity v.

v = sqrt ( μ g r ) = sqrt ( ( .74 ) ( 9.8 m / s² ) ( 29.6 m ) )