How do i solve 1<3+Z<6?

3 ⤊

2007-12-09 06:21:04 · 4 answers · asked by suzii jane 1 in Science & Mathematics ➔ Mathematics

- 2 < Z < 3

2007-12-09 06:37:07 · answer #1 · answered by Como 7 · 3⤊ 0⤋

1 - 3 < 3+z-3 < 6-3
-2 < z < 3

2007-12-09 14:23:53 · answer #2 · answered by antone_fo 4 · 0⤊ 0⤋

you create two Inequalities out of one:

(1) 3 + z > 1
(2) 3 + z < 6

(1) z > 1 - 3
(2) z < 6 - 3

(1) z > -2
(2) z < 3

the answer is:
-2 < z < 3

2007-12-09 14:31:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋

It's easier if you just separate them into two different problems to solve...
1<3+z and 3+z<6
-2 then you just combine them again and get
-2

2007-12-09 14:30:50 · answer #4 · answered by amodio 5 · 0⤊ 0⤋