A 31 kg box is at rest on a tuck. Static friction is 0.243. Acc. of gravity is 9.81 m/s^2. what is the max accel. the truck can go before losing the box? Help please, physics hw
2007-12-09 05:59:48 · 3 answers · asked by allda_jedi8472 1 in Education & Reference ➔ Homework Help
cpiratefreak's answer is fine but I'll go ahead and lay out the math for you...
F = ma = μmg so maximum acceleration a = μg.
2007-12-09 07:26:01 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
truthfully, the a = 2.ninety 4 (Mass)(acceleration)=(coeff)(mass)(grav... pull of Earth) (3 hundred)(acceleration)=(.30)(3 hundred)(9.8) Divide the two facets by way of the mass or 3 hundred as a effect.. (acceleration)=(.30)(9.8) a=2.ninety 4
2016-11-14 05:08:08 · answer #2 · answered by ritzer 4 · 0⤊ 0⤋
you have to find the force of gravity by multiplying the acc of gravity by the mass. that is equal to the normal force. you multiply the normal force by the friction. make that equal to (mass times acceleration), divide by the mass, and you should get acceleration
2007-12-09 06:10:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋