What change in volume results if 60.0 ml of gas is cooled from 33.0°C to 5.00°C?

Question

Please show work and use significant figures?

Answer 1

Equation between Volume and Temperature

V1/T1=V2/T2

V=volume in Liters
T=Temperature in Kelvin

V1=Convert 60mL into Liters. 60mL* (1L/1000mL)= .06 L
V2=UNKNOWN HAHA
T1= convert Celsius into Kelvin 33+273.15=306.15K
T2=278.15K

Renew equation to find volume:

V2=(T2*V1)/T1

(278.15*.06)/306.15= .054512 L

If you want the volume in mL then .054512L* (1000Ml/1L)=
54.512mL

The final answer with sig fig is!!!! 54.5 mL

Answer 2

Charle's Law. Pressure constant.
V1 x T2 = V2 x T1
60mL x 278K (5°C) = V2 x 306K (33°C).
Final Volume (V2) = (60 x 278) ÷ 306 = 54.5mL.

Answer 3

Use the relationship:

V1/T1 = V2/T2 for this.

Just remember to change your temperatures to Kelvin.

Answer 4

there is no change if it is liquid
unles it is a vapor then it condenses to liquid or depending on the gas to a solid all dependent on the nature of the chemical composition of the gas