Calculate the smallest cohesive force holding a 1.00 g bit of grit on the edge of the disc.?

Question

A grinding disc is turning 12900 rpm. The disc has a diameter of 20.0 cm. Calculate the smallest cohesive force holding a 1.00 g bit of grit on the edge of the disc.

minimum Centripetal Force = ________________ N

Answer 1

centrepatal acceleration = radius times omega squared

omega is angular velocity, so you need to convert rpm to radians per second.

also convert your radius to meters (0.1m)

Once you get your acceleration, use F= ma to get force

Answer 2

If the grit is hanging on, it's accelerating at this rate:

a = ω²r

where "ω" is the disc's angular velocity in radians per second. There are 2π radians in a revolution. So convert from rpm to rad/sec:

ω = 12900(2π) radians / (60 sec) = 1350.9 rad/sec

Use "F=ma" to figure the force required to produce this acceleration:

F = ma
F = m(ω²r)

They give you "m" and "r", and you figured "ω" above. Solve for "F".

Answer 3

i think that