basically i need to know what this is equal to:
[ (3x - 1)^1/3]^2
thanks
2007-12-09 01:51:02 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
according to law of indices, [(a)*b]*c = a*(bc) hence multiplication of indices: 1/3*2=2/3
therefore, answer= (3x-1)*2/3
2007-12-09 02:03:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
We know that (a^m)^n=a^(mn)
Hence the above expression will be reduced to
(3x - 1)^(2/3)
2007-12-09 10:01:16 · answer #2 · answered by kartheek 2 · 0⤊ 0⤋
I think it could be zero (0) but then again my maths pass was only a grade A GCSE (Got 2 points tho)
Our lives must be lacking doing this on a Sunday afternoon!
2007-12-09 10:03:17 · answer #3 · answered by Vanilla Icequeen 2 · 0⤊ 0⤋
[ (3x - 1)^1/3]^2 = (3x - 1)^2/3
This is saying take cube root of (3x-1)^2
2007-12-09 10:02:52 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
When you have exponents in brackets, you multiply them out. For example, (a^2)^4 really equals a^8. Hope that helps you.
2007-12-09 09:56:38 · answer #5 · answered by Alex S 2 · 0⤊ 0⤋
I'v got 9x probably wrong but then I only do these to keep my old brain active
2007-12-09 10:14:50 · answer #6 · answered by Paddy 4 · 0⤊ 0⤋