find 2log_6 (3) + log_6 (24)?

2 ⤊

find 2log_6 (3) + log_6 (24)?

2007-12-08 22:34:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

2log_6(3) + log_6(24)
= log_6[(3^2)(24)]
= log_6[3^2*2^2*6]
= log_6[6^3]
= 3log_6(6)
= 3

2007-12-08 22:41:54 · answer #1 · answered by sv 7 · 0⤊ 1⤋

2007-12-09 06:42:07 · answer #2 · answered by Hosu A 2 · 0⤊ 0⤋

log A + log B (to the same but any base) = log A*B
2log_6(3) = log_6(3^2) = log 9 ( base 6 let it be understood)
â´ log 9 + log 24 = log (9*24)=log 216 = log 6^3= 3log 6 = 3 ( as log of 6 to base 6 = 1)

2007-12-09 06:49:32 · answer #3 · answered by aditya 1 · 0⤊ 1⤋

log is log base 6 in the following:-

log 3Â² + log 24
log (9 x 24)
log 216
3

2007-12-09 06:44:46 · answer #4 · answered by Como 7 · 2⤊ 0⤋