help KIRCHOFFS PROBLEM MATHS!!!!! 10 POINTS NOW!?

Question

hi can anyone help me do this as im new to this kind of maths could u show me the calculations as well please THANK YOU 10 POINTS FOR GOOD ANSWER !!!


HERES THE Q!!
http://i136.photobucket.com/albums/q200/batista981/kirchogffsfsf.jpg

Answer 1

The first one is a series circuit - the same current passes through all resistors.

You add all of the resistors together for part a.
then use Ohm's law to calculate the current:
I = E/R so the current I = 24 volts / total loop resistance
For the voltage drops across each resistor, use Ohm's law:
E = I * R you know the current from part a, and you are given the resistor values.

in the second problem, the 3 parallel resistors on the left must be converted to an equivalent single resistor
Req = R1 * R2 / (R1 + R2)
and the three resistors in parallel on the right need to be combined to a single resistor using an expanded version of the formula for 2 resistors above.

Then solve this as you did the first problem

Answer 2

You are going about this problem the wrong way. First set the equation equal to zero. 0= -X^2+2x+4 (notice the neg. symbol in front of the X^2. This equation can not be factored or "distributed into paretheses" as you call it so you have to use the quadratic formula. the quadratic formula contains 3 variables... A, B, and C. For this equation you have A= -1, B=2, C=4. Plug in and solve for X. X= 1+2√5 /-2 simplify and you have your answer! Obviously no matter what you do you will not get a √6 so C is out... and if A is correct then what happened to the 2 before the √5? So A is wrong also... that leaves you with... B. Final Answer.

Answer 3

Question 1
a) 24 Ω
b) 1 A
c) V1 = 6V , V2 = 8V , V3 = 10V

Question 2
Part a)
1 / R1 = 1/6 + 1/12 = 3/12
R1 = 4 Ω

1/R2 = 3/24 + 2/24 + 1/24 = 6/24
R2 = 4 Ω

R = 8 Ω

Part b)
I = 20/8 A = 2.5 A

Part c)
I1 = 2/3 x 2.5A = 5/3 A = 20/12 A
I2 = 5/6 A = 10/12 A
Sum = 30/12 A = 2.5A (as required)

I3 = 10/8 A = 5/4 A = 15/12 A
I4 = 10 / 12 A
I5 = 10/24 A = 5 / 12 A
Sum = 30/12A = 2.5 A (as required)

Answer 4

a=24Ω
b=1 amp
c = 6v - 8v - 10v
--
u do the rest