how do i calculate log_n 64 = 2?

Answer 1

Take the nth power of each side

So we end up with

64 = n^2

So we want a number that, when squared, equals 64.

The answer is positive or negative 8

Answer 2

64=2^6
log_n 64 = 2
log_b a=c
a=b^c
a=64,c=2 Thus,64=n^2
2^6=n^2
2^(2*3)=n^2
8^2=n^2
n=8

Answer 3

64 = 8²
log8 64 = 2
n = 8

Answer 4

just 8, you cant have logs with the base of negative numbers, (well you can, but would not be a continuous function, and thus not very useful). not that -8 squared isn't 64

Answer 5

log[base n](64) = 2

Convert to exponential form. Recall that
b^c = a if and only if log[base b](a) = c.

n^2 = 64

Solve for n. If I recall correctly, the base of a log can never be negative; therefore, although

n = +/- 8

We reject the negative solution.

Answer 6

it is asking:
n^2 = 64
therefore n = ±8