1) 3(x-4)^2= -27
2) x^2 +4x =-5
2007-12-08 21:54:42 · 4 answers · asked by iju 2 in Education & Reference ➔ Homework Help
3(x-4)^2= -27
(x-4)^2= -27/3
(x-4)^2= -9
(x-4)= 3i
x=3i+4
x^2 +4x =-5
x^2 +4x +5=0
d=16-20
d=-4
x=(-4+-2i)/2
x=-2+-i
x=-2+i or x=-2-i
2007-12-08 22:01:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1) 3 ( x - 4 ) ^ 2 = - 27
-------( x - 4 ) ^ 2 = - 27 : 3
------- ( x - 4 ) ^2 = - 9 (unacceptable)( square root of everything has to be positive)
==> x has no answer.
2007-12-08 22:45:22 · answer #2 · answered by Nai 4 · 0⤊ 0⤋
yep - YOU can do it
your homework
1) distibute the numbers out - then add 27 to both sides - solve
2) add 5 to both sides - solve
2007-12-08 21:57:50 · answer #3 · answered by tom4bucs 7 · 0⤊ 0⤋
Please log on to extramarks.com
you will get the desired result
2007-12-08 22:34:51 · answer #4 · answered by sweet f 1 · 0⤊ 0⤋