Did I do this correctly to find the volume of hydrogen given off using this balanced equation (see details)?

Question

Here's the equation:

Zn + 2HCl ---> ZnCl2 + H2

The first two is a regular number and the other two 2's are supposed to be subscripted.

Would that make it 44.8 L of hydrogen?
It's OK to assume STP on this, according to my teacher.
Since it's H2, which would be 2 moles of hydrogen, and one mole = 22.4 L, it's 44.8 L.

Did I do that right?

2.4301 g of Zinc is used.

Answer 1

How much Zn is used? There will be two moles of H2 only if two moles of Zn are reacted.

EDIT after seeing your comment. The atomic mass of Zn is 65.38 g/mole 2.4301 g is then 2.4301/65.38 moles = 0.0372moles, so the reaction produces 0.0372 moles of H2, which has a volume of 22.4*0.03712 L = 0.833 L

Answer 2

no you made a mistake,
the molar mass of zinc is 55.4
0.0439 mols of zinc x 1 = 0..0439 mols of H2 gas
0.0439 x 22.4 = liters of H2 gas

when the 2 is a subscript it tells how the atoms are grouped by being bonded. 2 mols of H atoms are bonded to one another but they only make 1 mol of H2 gas. 44.8 should not be used here