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a potter's wheel moves from rest to an angular speed of 0.20 rev/s in 30.0 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2?

2007-12-08 15:56:51 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

angular acceleration = change in angular speed / time over which change occurs

so 0.20 rev/s divided by 30.0 s is the answer in rad/s^2

2007-12-08 16:06:17 · answer #1 · answered by michaelmgkdn 2 · 0 0

w = @ X T where T= time, @ = angular acceleration and w = final angular velocity

2007-12-09 00:00:19 · answer #2 · answered by LucaPacioli1492 7 · 0 0

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