_2m+1___=__3m-2__
3 5
i wasn' sure how to type in these kind of fractions but thats what they r suppost to be LOL
2007-12-08 15:40:05 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the 2m+1 is over 3 and the 3m-2 is over 5 when i submitted the question it turned to 35 thats not what the question is
2007-12-08 15:41:14 · update #1
first, times both sides by 3
1. 2m+1 = 3 ( 3m-2/5) multiply it out on the right side
2. 2m +1 = 9m-6 /5
3. then multiply both sides by 5
4. 10m+5 = 9m-6
5. then subtract 9m from both sides
6. 1m+5 = -6
7. then subtract 5 from both sides
8. 1m= -11
thus, m =-11
2007-12-08 15:49:22 · answer #1 · answered by Susie Q 2 · 0⤊ 0⤋
2m+1 = 3m-2
3 5
2m+1 - 3m-2 =0
3 5 5(2m+1) – 3(3m-2) =0
15
10m+5-9m+6 =0
15
After this stage you will have to group the like terms, then do the necessary operations.
2007-12-09 00:06:16 · answer #2 · answered by Tiffia 2 · 0⤊ 0⤋
Get rid of denominator first.
Multiply both sides by 15
15 (2m+1)/3= 15 (3m-2/5
= 10m +5 = 9m-6
m=-11
2007-12-08 23:52:06 · answer #3 · answered by ? 5 · 0⤊ 0⤋
I assume it is
(2m+1)/3 = (3m-2)/5
5(2m+1)=3(3m-2)
10m+5=9m-6
m=-11
2007-12-08 23:45:35 · answer #4 · answered by norman 7 · 0⤊ 1⤋
cross multiply: 3 times (3m-2) = (2m+1) times 5.
Then you can just solve for m.
2007-12-08 23:46:23 · answer #5 · answered by Andy I 2 · 0⤊ 1⤋