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an artifical cell with an aqueous solution in a a selectively permeable membrane has just been immersed in a beaker containing a different solution.

Inside the cell, there is .03 M glucose and 0.2 M sucrose and in a beaker, it is .01 M sucrose, .01 glucose, and .01 M fructose

the question is : which solutes will exhibit a net diffusion into the cell?
A Glucose
B Sucrose
C Frcutose
D both b and a

2 Question: after the cell is placed into the beaker, which of the following changes would occur?

A. the artifical cell would become more flaccid ( weak)
b. The artifical cell would become more tugid
C. the membrane potenital would decrease
D. the entropy of the system ( cell plus surrounding solution ) would decrease

all the help would be appreciated

thanks guys

2007-12-08 14:01:04 · 4 answers · asked by meee 2 in Science & Mathematics Biology

4 answers

1) "C" appears to be the most reasonable answer.

2)Looks like the system is hypotonic to the cell and will
therefore cause an inward osmosis. Answer is "B".

2007-12-08 16:09:19 · answer #1 · answered by ursaitaliano70 7 · 0 0

1. I don't know. If the membrane is permeable to fructose, then the answer is
C. Fructose.

The principle here is that fructose has a greater concentration outside the cell than inside.

2. Again, I don't know. Let's say that the membrane is impermeable to sucrose. If that's the case, then the answer is
B The artifical cell would become more turgid
The reasoning is that there's a greater concentration of solutes inside the cell, the solute (sucrose) can't diffuse out, and water can diffuse in... and water will diffuse inward (osmosis).

2007-12-08 14:50:42 · answer #2 · answered by Anonymous · 0 0

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2016-12-17 11:50:29 · answer #3 · answered by ? 4 · 0 0

c and d

2007-12-08 14:59:18 · answer #4 · answered by Tigger 1 · 0 0

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