Calculus I : what is the limit as x approaches 0 of 2x / [ (sinx)-x ]?

Question

can't figure it, I must have forgot something, thanks

i haven't learned about the L'Hopital's Rule yet, is there another way?

Answer 1

Use L'Hopital's Rule

derivative of 2x is 2
derivative of sin x - x is cos x - 1

lim ( x → 0 ) of 2 / ( cos x - 1 ) = -∞