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2007-12-08 12:35:09 · 1 answers · asked by MareK D 1 in Science & Mathematics Mathematics

1 answers

h(w)=−15 w^−12 + 4√w
h(w)=−15 w^(−12) + 4w^(1/2)

h'(w) = ( -15 ) ( -12 ) w^( -13 ) + ( 4 ) ( 1/2 ) w^( -1/2 )

2007-12-08 12:39:01 · answer #1 · answered by jgoulden 7 · 0 0

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