Can someone please help me with the chemistry question asked below?

Question

A particular coal contains 4.3% sulfer by mass as an impurity. When the coal is burned, the S is converted to gaseous SO2. The SO2 enters the exhaust gases, where it is removed by reaction with powered CaO to produce solid CaSO3. How much by-product CaSO3, in tons, is produced by the burning of 1 ton of coal?
(please include equations)

Answer 1

First find moles of sulfur in the coal:

[2000lb x 454g/lb x 0.043]/32g/mole =

1220moles of sulfur

Since one mole of sulfur corresponds to one mole of calcium sulfite we will get 1220moles of calcium sulfite, which we can convert back to tons:

CaSO3 weighs [(40 + 32 + (3 x 16)] or 120g/mole

1220moles x 120g/mole x 1kg/1000g x

2.2lb/kg 1ton/2000lb = 0.161ton

Answer 2

one ton of coal has 0.043 tons of sulfur

Wt. of

Ca = 40
S=32
O=16

so wt of CaSO3= 40+32+16+16+16 = 120

Ratio of wts of CaSO3 to S = 120/32 = 3.75

so wt of CaSO3 produce if 0.043 tons of S is available is

3.75 x 0.043 = 0.16125 tons of CaSO3 (322.5 lb)

Answer 3

1 ton = 2000 lbs
2000 lbs x 0.043 = 86 lbs S
86 lbs x 453.6 = 39,010 gramd
39,010 g / 32.066 g/mol = 1,217 moles of S atoms
1217 moles of CaSO3 x 120.15 g/mol = 146,217 g CaSO3
146,217 g / 453.6 = 322 lbs CaSO3
322 lbs CaSO3 / 2000 lbs = 0.16 tons

The easy way-
1 ton x 0.043 x (120.15/32.066) = 0.16 ton

Answer 4

dude thats one hell of a question. you got to be kidding me lets see you do it