the radius of a circle is 50 cm. Find the length of a chord 14cm from the center.?

Answer 1

96 cm

as
if Cis the length of the cord &r is the radius &L is the distance from the center
r^2-L^2 =(C/2)^2
(C/2)^2 =50^2-14^2 =2304
c/2=48
c=96cm

Answer 2

The cord is 14 cm from the center. The radius is 50cm

There for you have a right triangle with a hypotenuse of 50cm
and a side of 14 cm.

c^2=A^2+b^2

50^2=14^2+b^2
2500=196 +b^2
b^2= 2304
b= 48

b is 1/2 of the length of the cord.

the cord is 96 cm in length

Answer 3

Draw a radius, which bisects a chord 14 cm from the centre.
Draw radii to each end of the chord, let x represent 1/2 length.
By Pythagoras, 50^2 = 14^2 + x^2
2500= 196+x^2
x= sqrt(2500-196)
x = sqrt(2304)
x=48
Chord is 96 cm

Answer 4

since the radius of the circle is 50cm and the chord is 14cm from the center each half of the chord can be considered one of the legs of a right triangle. thus through the pythagorean theorem one would get d=sqrt(50^2-14^2), where d is half of the chord. so ch=2d=2*sqrt(2500-196)=2*sqrt2304=2*48=96cm

Answer 5

Draw a chord through a circle.
Draw a radius.
From the center, draw a perpendicular bisector to the chord.
Chord breaks down to 7 cm.
With radius of 50, do a pathagorean formula.
50^2 - 7^2 = y^2
what is the answer?

Answer 6

[04]
Let the kebgth of half the chord be c
Therefore C^2+14^2=50^2
c^2=50^2-14^2
=2500-196
=2304
c=48 cm
Therefore length of the chord is 2*48 or 96 cm

Answer 7

3.57